Arithmetic and Algebra Again: Leaving Math Anxiety Behind by Britta Immergut, Jean Burr Smith

By Britta Immergut, Jean Burr Smith

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Additional resources for Arithmetic and Algebra Again: Leaving Math Anxiety Behind Forever, Second Edition

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The numbers are small, so the arithmetic will not be complicated. Try them this way: 1. 2. 3. 4. Read the problem through. Decide your strategy: whether to add, subtract, multiply, or divide. Get an answer. ” EXAMPLE How many hats, at 4 dollars apiece, can be bought with 20 dollars? Solution Strategy: divide. Here we divide 20 by 4 and find that 5 hats can be bought. EXAMPLE A man was 45 years old and had been married 19 years. How old was he when he married? Solution Strategy: subtract. 45 − 19 = 26 gives us the solution that he was 26 years old when he got married.

List all multiples of 7 between 80 and 100. Insert the correct symbol < or > between 75 and 31. Evaluate: 10 − 2[2 − (5 − 4) + 8 ÷ 4 × 2]. Tell which properties are illustrated in (7 + 2) + 3 = (7 + 3) + 2 10. A sum of four thousand eighty dollars is divided equally among four people. How much money does each person get? 2, each digit in a number has a name for its place. Starting from the rightmost digit in a whole number, we have the ones or units place. One step to the left takes us to the tens place, and the next position is the hundreds place.

Since 7 is more than 5, we add 1 to 3, and 3761 becomes 4000. 7, 6, and 1 are replaced by zeros. EXAMPLE Round 1431 to the nearest hundred. Solution The digit in the hundreds place is 4, and 3 is less than 5. Keep the 4, and make the digits to the right of it zeros. In other words, 1431 is closer to 1400 than it is to 1500. 28 PART I ARITHMETIC EXAMPLE Round 75,000 to the ten thousands place. Solution The digit in the ten thousands place is 7, and the following digit is 5. Our rule states that we add 1 to 7.

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